Respuesta :
Answer: The value of x is [tex]\frac{50}{3}[/tex]
Step-by-step explanation:
Let the original price of gasoline be y
Since we have given that
Price of gasoline rose by 20% during January fell by 20% during February rose by 25% in March and fell by x% in April.
So, According to question,
In January, Price became
[tex]\frac{100+20}{100}\times y=\frac{120}{100}\times y=\frac{6}{5}\times y=\frac{6y}{5}[/tex]
Similarly, In February, Price became
[tex]\frac{100-20}{100}\times \frac{6y}{5}=\frac{80}{100}\times \frac{6y}{5}=\frac{4}{5}\times \frac{6y}{5}=\frac{4}{5}\times \frac{6y}{5}=\frac{24y}{25}[/tex]
Similarly, in March, Price became,
[tex]\frac{100+25}{100}\times \frac{4\times 6y}{25}=\frac{125}{100}\times \frac{6\times 4y}{25}=\frac{5}{4}\times \frac{24y}{25}=\frac{5}{4}\times \frac{24y}{25}=\frac{6y}{5}[/tex]
similarly, in April , Price became,
[tex]\frac{100-x}{100}\times \frac{6y}{5}[/tex]
so, we have given that the price of gasoline at the end of April was the same as it had been at the beginning of January.
So, it becomes,
[tex]\frac{6y}{5}\times \frac{100-x}{100}=y\\\\6(100-x)=500\\\\600-6x=500\\\\600-500=6x\\\\100=6x\\\\x=\frac{100}{6}=\frac{50}{3}[/tex]
Hence, the value of x is [tex]\frac{50}{3}[/tex]
Answer:
x= 16 2/3
Step-by-step explanation:
Price will be p
The price in January increases by 20%, it will be 6p/5. The price in February decreased by 20%, it becomes 24p/25. The price in March rose by 25%, it will be 6y/5.
April: 6y/5 times 100-x/100 = p 6(100-x)=500 100=6x x= 16 2/3
