Two skateboarders start a race at the same time. Skateboarder A travels at a steady rate of 15 feet per second. Skateboarder B travels at a steady rate of 22 feet per second. After 4 minutes, how much farther will Skateboarder B have traveled?

Respuesta :

So covert 4 minutes to seconds. Which would be 4 times 60 which would mean there would be 240 seconds. So you would multiply 15 x 240 = 3,600 feet. Then multiply 22 x 240 = 5,280 feet. 5,280 - 3,600 = 1,680 feet.

ANSWER:
Skateboarder B will have traveled 1,680 more feet over 4 minutes.

Relative speed can play a major role in creating distance between two bodies. If the relative speed between two bodies is 0, then both the bodies are moving in the same direction with a similar speed. Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

Skateboarder A travels at a steady rate of 15 feet per second.

Skateboarder B travels at a steady rate of 22 feet per second.

We need to determine that after 4 minutes, how much farther will Skateboarder B have traveled.

The formula for finding the distance travelled by anybody is represented below:

[tex]\rm{Distance}=\rm{Speed} \times \rm{Time}[/tex]

Time is given that is 4 minutes which means 240 seconds.

Thus,

Distance travelled by skateboarder A.

[tex]\begin{aligned}\rm{Distance\;of \;A}&=\rm{15} \times \rm{240}\\&=3600\;\rm{feet}\end{aligned}[/tex]

Distance travelled by skateboarder B.

[tex]\begin{aligned}\rm{Distance\;of \;B}&=\rm{22} \times \rm{240}\\&=5280\;\rm{feet}\end{aligned}[/tex]

Therefore, the separation of the distance between both the skateboarders is 5280 - 3600 = 1680.

Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

To know more about relative speed, please refer to the link:

https://brainly.com/question/13430965