What is a point-slope equation of the line with slope –13 that goes through the point (5, 7)? A.y – 7 = –13(x – 5) B.y – 5 = –13(x – 7) C.y + 5 = –13(x + 7) D.y + 7 = –13(x + 5)

Respuesta :

The correct answer is A.

We can prove this by substituting the values in ourselves.

The formula for point-slope is the following y-y1=m(x-x1).

M= slope

y1 and x1= y and x coordinates of a point.

point= (x,y)

We substitute in the values.

y-7=-13(x-5)

and we get the exact same equation from option A proving it correct.


Hope this helps!

The point-slope equation of the line with slope –13 passing through the point (5, 7) is Option (A) y - 7 = -13(x - 5)

Finding the point-slope equation of a straight line -

What is a point-slope equation of straight line ?

A point-slope equation of a straight line is an equation which represents a straight line passing through the points (x1,y1).

The point-slope formula for the line is given as -

y - y1 = m(x - x1)

Where, m is the slope of the given straight line

x1 and y1 are the respective x and y coordinates of the points through which the line passes.

In the problem, slope given is -13 also the point given is (5,7) which means x1 = 5 and y1 = 7 .

Thus putting the values of problem in the point-slope formula of straight line,

y - 7 = -13(x - 5)

Therefore we yield the result of equation of the straight line in point-slope form.

To learn more about point-slope form of straight line, refer -

https://brainly.com/question/6497976

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