You want to make five - letter codes that use the letters A, F ,E ,R and M without repeating any letter. What is the probability that a randomly chosen code starts with M and ends with E?

A) 0.01
B) 0.02
C) 0.05
D) 0.10

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brycefoster brycefoster · Answer 1 · 2018-11-15T16:01:57+01:00

Any of the given 5 letters can be at the start of the code.

Total choices = 5

We want the code to start with A

Choices in favor = 1

Probability = favorable/total = 1/5 = 0.20

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alinakincsem alinakincsem · Answer 2 · 2018-11-15T16:57:52+01:00

Answer:

The correct answer option is C) 0.05

Step-by-step explanation:

We are given five different alphabets A, F ,E ,R and M and with the help of these, we want to make five letter codes without repeating ant letter.

Since, each letter can be used once so the probability of picking a M first = [tex]\frac{1}{5}[/tex].

Now we want the following sequence:

(not E, not E, not E) = [tex]\frac{3}{4} *\frac{2}{3} *\frac{1}{2}[/tex] = [tex]\frac{1}{4}[/tex]

So the probability that a randomly chosen code starts with M and ends with E = [tex]\frac{1}{5} *\frac{1}{4}[/tex] = [tex]\frac{1}{20} = 0.05[/tex]