Respuesta :
Answer:
Original size of population containing fruit files = 10 files
Rate at which population of fruit file is increasing = 22.5%
New population of fruit files having initial population of 10 files and increase rate of 22.5% is given by =
10 + 22.5 × [tex]\frac{10}{100}[/tex]
= 10 + 22.5 × [tex]\frac{1}{10}[/tex]
= 10+ 2.25
= 12.25 files
Answer:
Original size of population containing fruit files = 10 files
Rate at which population of fruit file is increasing = 22.5%
New population of fruit files having initial population of 10 files and increase rate of 22.5% is given by =
10 + 22.5 ×
= 10 + 22.5 ×
= 10+ 2.25
= 12.25 files