Respuesta :

Answer:

Original size of population containing fruit files = 10 files

Rate at which population of fruit file is increasing = 22.5%

New population of fruit files having initial population of 10 files and increase rate of 22.5% is given by =

                                              10 + 22.5 × [tex]\frac{10}{100}[/tex]

                                         = 10 + 22.5 × [tex]\frac{1}{10}[/tex]

                                         = 10+ 2.25

                                           = 12.25 files




Answer:

Original size of population containing fruit files = 10 files

Rate at which population of fruit file is increasing = 22.5%

New population of fruit files having initial population of 10 files and increase rate of 22.5% is given by =

                                             10 + 22.5 ×  

                                        = 10 + 22.5 ×  

                                        = 10+ 2.25

                                          = 12.25 files