Answer: [tex]-4.5 m/s^2[/tex]
Explanation:
The average acceleration of the car is given by:
[tex]a=\frac{v-u}{t}[/tex]
where
u = 45 m/s is the initial velocity
v = 0 m/s is the final velocity
t = 10 s is the time taken
Substituting the numbers into the equation, we find
[tex]a=\frac{0 -45 m/s}{10 s}=-4.5 m/s^2[/tex]