please help me out !!!




Answers: x = [tex]\frac{25}{4}[/tex] , arc AB = 110°, x = [tex]\frac{4}{3}[/tex], arc AB = 56°
Explanation:
Set up the proportion then cross multiply and solve for x.
[tex]\frac{MQ}{QP} = \frac{MN}{NO}[/tex]
[tex]\frac{15}{x} = \frac{12}{5}[/tex]
15(5) = x(12)
75 = 12x
÷12 ÷12
[tex]\frac{75}{12}[/tex] = x
[tex]\frac{25}{4}[/tex] = x reduced
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arc ADB + arc AB = 360°
250° + AB = 360°
-250° -250°
AB = 110°
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Set up the proportion then cross multiply and solve for x.
[tex]\frac{MQ}{QP} = \frac{MN}{NO}[/tex]
[tex]\frac{4}{x} = \frac{6}{2}[/tex]
4(2) = x(6)
8 = 6x
÷6 ÷6
[tex]\frac{8}{6}[/tex] = x
[tex]\frac{4}{3}[/tex] = x reduced
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Central angle = measure of the arc
∠AB = arc AB
56° = arc AB