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What would be the change in pressure in a sealed 10.0 L vessel due to the formation of N2 gas when the ammonium nitrite in 1.00 L of 0.500 M NH4NO2 decomposes at 25.0°C?

Respuesta :

itsyourgirll

First, let's find the number of moles of ammonium nitrite.


0.5 mol/L * 1.10 L = 0.6 mol


The decomposition reaction is


NH₄NO₂ → N₂ + 2 H₂O


Let's calculate the amount of N₂ gas produced.


0.6 mol * 1 mol N₂/1 mol NH₄NO₂ = 0.6 mol N₂


Then, let's compute P through the ideal gas equation:

P = nRT/V

P = (0.6)(0.0821 L-atm/mol-K)(25+273 K)/10 L

P = 1.47 atm


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