The problem is:
[tex]\frac{\frac{3}{x}+\frac{1}{4}}{1+\frac{3}{x}}[/tex]
We now do L.C.M. of numerator and add, also do L.C.M. of denominator and add together:
[tex]\frac{\frac{12+x}{4x}}{\frac{x+3}{x}}[/tex]
Dividing by a fraction is same as multiplying by its reciprocal, so we have:
[tex]\frac{12+x}{4x} * \frac{x}{x+3} \\[/tex]
x cancels out, so can multiply and write:
[tex]\frac{12+x}{4} * \frac{1}{x+3} \\=\frac{12+x}{4x+12}[/tex]
This is the simplified form.
ANSWER: [tex]\frac{12+x}{4x+12}[/tex]
