Start with
[tex] 3r \leq 4r-6 [/tex]
Subtract [tex] 3r [/tex] from both sides:
[tex] 0 \leq r - 6 \iff r-6 \geq 0 [/tex]
Add 6 to both sides:
[tex] r \geq 6 [/tex]
So, All numbers greater than or equal to 6 are ok: the solution is the first set:
[tex] A = \{6,\ 7,\ 8,\ 9,\ 10\} [/tex]