Answer: The equation of a line that is parallel to y=6x+7 and passes through (0,9) is y=6x+9.
Explanation:
The equation of given line is
[tex]y=6x+7[/tex]
The slope intercept form of a line is,
[tex]y=mx+b[/tex]
Where, m is slope and (0,b) is y intercept.
On comparing the given equation with slope intercept form we get,
[tex]m=6[/tex]
The slope of the given line is 6.
Since the slope of parallel line are equal, therefore the slope of required line is 6.
The point slope form of a line.
[tex]y-y_1=m(x-x_1)[/tex]
The slope of required line is 6 and it passing through the point (0,9),
[tex]y-9=6(x-0)[/tex]
[tex]y=6x+9[/tex]
Therefore the equation of a line that is parallel to y=6x+7 and passes through (0,9) is y=6x+9.
