Given that BD is the median of abc and that abc is isosceles congruence postulate sss can be used to prove which of the following?

Answer: The correct option is D.
Explanation:
It is given that the triangle ABC is an isosceles triangle. It is also given that the line BD is the median of triangle ABC.
Since DB is median it means point D divides the line AC in two equal parts.
The The median of an isosceles triangle is always a perpendicular bisector of the opposite side. Since the median is perpendicular on side AC, therefore the sides AB and CB are equal.
In triangle ABD and CBD,
[tex]AB=CB[/tex] .... (Isosceles triangle)
[tex]AD=CD[/tex] .... (D is midpoint of AC)
[tex]BD=BD[/tex] .... (Common Side)
Therefore option D is correct.
The ABC is isosceles congruence postulate sss. It can be used to prove the option D.
The following information should be considered:
Therefore we can conclude that the ABC is isosceles congruence postulate sss. It can be used to prove the option D.
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