coolio
[tex]t_1=11[/tex]
[tex]t_n=t_{n-1}-13[/tex]
so each term is ound by subtracting 13 from the previous term
an aritmetic sequence can be written as
[tex]t_n=t_1+d(n-1)[/tex] were
[tex]t_n[/tex] is the nth term
[tex]t_1[/tex] is the first term
d is common difference, which can also be found by doing [tex]t_n-t_{n-1}=d[/tex]
n=wich term
we know that [tex]t_1=11[/tex] and we can find d
[tex]t_n=t_{n-1}-13[/tex], [tex]t_n-t_{n-1}=-13=d[/tex]
so te general term is [tex]t_n=11-13(n-1)[/tex] which can also be expanded and written as [tex]t_n=-13n+24[/tex]
Answer:
Tn= 11 - 13(n-1), where n ∈N and n ≥ 1
Step-by-step explanation:
I took the test, that's the right answer
hope this helps
