Which expression is equivalent to the following complex fraction?
1/x-1/y / 1/x+1/y

A. y+x/y-x
B. (y-x)(y+x)/ x^2 y^2
C. x^2 y^2/ (y+x) (y+x)
D. y-x/y+x

Respuesta :

Answer: (D) [tex]\frac{y-x}{y+x}[/tex]

Explanation:

[tex]\frac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}=\frac{\frac{y-x}{xy}}{\frac{y+x}{xy}}=\frac{y-x}{y+x}[/tex]

Just a note on writing down these expressions: I recommend using parentheses whenever you can to avoid misinterpretation. An expression 1/x-1/y / 1/x+1/y could be interpreted by someone as 1/x-(1/y / 1/x)+1/y, which is a different thing.

Answer:

The correct answer is D. y-x/y+x

Step-by-step explanation:

I just took the unit test review. :)

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