The molarity of AgNO3 is 0.401 M
calculation
Step 1: write the chemical equation for reaction
MgCl2 + 2AgNO3 → Mg(No3)2 + 2 AgCl
Step 2: calculate the moles of MgCl2
moles = molarity x volume in liters
volume in liters=22/1000= 0.022 L
molarity = 0.137 M or 0.137 mol/L
moles is therefore= 0.137 mol/l x 0.022 L =3.01 x10^-3 moles
Step 3: use the mole ratio to determine the moles of AgNO3
The mole ratio of MgCl2: AgNO3 is 1:2 therefore the moles of AgNo3 is
= 3.01 x 10^-3 moles x 2/1= 6.02 x 10^-3 moles
Step 4: find the molarity of AgNO3
molarity = moles /volume in liters
volume in liters = 15/1000=0.015 L
molarity is therefore =( 6.02 x 10^-3) /0.015 = 0.401 M
