1. The slope of the given lines is the x-coefficient, 1/3. The opposite reciprocal of that is -1/(1/3) = -3. We simply need to replace the slope in one of the slope-intercept equations. Using the first one, we find the equation of the perpendicular line to be ...
... y = -3x +1
2. The above equation together with the second given equation form the system of interest:
Subtracting the first equation from the second, we get ...
... (1/3x -2) -(-3x +1) = 0 = (3 1/3)x -3
... 3 = (10/3)x . . . . . . . . add 3
... 9/10 = x . . . . . . . . . . multiply by 10/3
We can substitute this value into either above equation to find y. Using the first, we have ...
... y = -3(9/10) +1 = -2.7 +1 = -1.7
The solution to the system is (x, y) = (0.9, -1.7).
3. The distance formula tells us the distance can be found from the sum of squares of the differences in coordinates.
The points on either line where the perpendicular intersects are ...
... (0, 1) and (0.9, -1.7)
The differences between these points are (∆x, ∆y) = (0.9, -2.7), so the distance between the points is ...
... d = √(0.9² +(-2.7)²) = √8.1 = 0.9√10
In decimal form, d ≈ 2.8460499
... d ≈ 2.85
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Comment on distance between parallel lines
The distance from a point to a line can be found using a formula based on the general-form equation of a line. For line ...
... ax +by +c = 0
The distance from point (x, y) to the line is given by
... d = |ax +by +c|/√(a²+b²)
The two lines we have can be rearranged to general form as ...
We know that any point on the first line will satisfy x -3y = -3. Substituting this value into the distance equation for the distance to the second line, we get ...
... d = |-3 -6|/√(1²+(-3)²) = 9/√10 = 0.9√10
In my opinion, this is a much easier way to find the distance between parallel lines.
[tex]y=\frac{1}{3}x+1[/tex] an [tex]y=\frac{1}{3}x-2[/tex]
the step are the right way to solve so great,
step 1: find perpendicular
perpendicular lines have slopes that multiply to get -1,
however they don't have to have the same y-intercept, so b in y=mx+b can be literally any number, but the problem wants you to use one of the other
let's use b=1 from 1st equation
also, slope, 1/3 times ?=-1, ?=-3
y=-3x+1 is perpendicular equation
step 2:
using te other equation y=1/3x-2 an find intersection
y=-3x+1 and y=1/3x-2
subsitute
-3x+1=1/3x-2
multiply both sides by 3
-9x+3=x-6
add 9x both sies
3=10x-6
add 6 both sides
9=10x
divide by 10
9/10=x
in y
y=-3x+1
y=-3(9/10)+1
y=-27/10+1
y=-27/10+10
y=-17/10
so point o intesection is (9/10,-17/10) or (0.9,-1.7)
step 3:
find distance between (0,1) an (0.9,-1.7)
distance formula
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]d=\sqrt{(0.9-0)^2+(-1.7-1)^2}[/tex]
[tex]d=\sqrt{(0.9)^2+(-2.7)^2}[/tex]
[tex]d=2.84605[/tex]
round
d=2.85
