Na: 22.99 grams; H: 1.008 grams; P: 30.97 grams; 0: 16.00 grams
The molar mass of sodium phosphate (Na2HPO4) would be equal to:
(2 x 22.99) + 1.008 + 30.97 + (4 x 16) = 141.96 grams/mole
Calculation for sodium phosphate dihydrate (NaH2PO4 2H20) the same way as above:
22.99 + (2 x 1.008) + 30.97 + (4 x 16) + (4 x 1.008) + (2 x 16) would equal 156.01 grams/mole
Hope this helped! If not, then at least I tried. I think you put like terms together for the 1Li + 5B + 9Br thing, but I am not 100% sure.
2 x 22.99 + 4 x 16 = 8 x 367.84 = 2,942.72 (2,943)
22.99 + 30.97 = 53.96 (54Li Maybe?)
2 x 1.008 + 4 x 1.008 = 8 x 2.016 = 9.008 (9B Maybe?)
4 x 16 + 2 x 16 = 8 x 256 = 2,048 (2,000Br Maybe?)
Not 100% sure. At least I tried. I am not that good at math, but I tried the absolute best I could on paper to get this answer.
