neat
in h(x) we notice that there are no x^2 terms,
we also notice that in f(x), the coeffent of the x^2 term is -5
in g(x), the coeffient of the x^2 term is also -5
in order to eliminate the x^2 terms, we must subtract one from another (since -5-(-5)=0), so the operation must be either f(x)-g(x) or g(x)-f(x)
we then can consider the constant term or the constant
if we look at the constant of h(x), we see that it is -14
in f(x) the constant is -6
in g(x) the constant is 8
we note that 14=-6-8, so g(x) must be multiplied by -1 then added to f(x)
ie f(x)-g(x)
if we check the linear term
in f(x), the linear term is 2x
in g(x) the linear term is -4x
if we do f(x)-g(x), the linear term will be 2x-(-4x)=2x+4x=6x which checks
the operation is f(x)-g(x)
answer is A
