Answer: The major ionic species present in the solution are sodium and sulfate ions.
Explanation:
Sodium sulfate is an ionic compound because it is formed by the complete transfer of electrons from sodium ions to sulfate ions.
When an ionic compound is dissolved in water, it dissociates into its corresponding ions.
The chemical equation for the ionization of sodium sulfate follows:
[tex]Na_2SO_4(aq.)\rightarrow 2Na^+(aq.)+SO_4^{2-}(aq.)[/tex]
By Stoichiometry of the reaction:
1 mole of aqueous solution of sodium sulfate produces 2 moles of sodium ions and 1 mole of sulfate ions.
Hence, the major ionic species present in the solution are sodium and sulfate ions.
Here, we are required to identify the major ionic species present in an aqueous solution of Sodium sulfate.
The major ionic species present in an aqueous solution of sodium sulfate are;
2Na+(aq.) and SO4²-(aq.)
Sodium sulfate has molecular formula: Na2SO4
When the solute is dissolved in water to yield an aqueous solution as insinuated in the question.
It's component ions split and therefore exist as individual ionic species in the solution.
The equation for the formation of this aqueous solution is as shown below;
Na2SO4(aq.) ----------->> 2Na+(aq.) + SO4²-(aq.)
The reaction above is possible because Na2SO4 is an ionic compound as it is formed by the complete transfer of electrons from the electropositive Na+ to the more electronegative SO4²- .
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