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A line is represented by the equation y/x-2=3/11. What are the coordinates of some points that line on the line?

Respuesta :

altavistard

y/x-2=3/11 would be easier to work with if we were to put it into a more standard form, e. g., y = mx + b.

First, add 2 to both sides, to isolate y/x:

y/x = 3/11 + 22/11 = 25/11.

Next, mult. both sides by x, to get y by itself:  y = (25/11)x.  

This is your function.

Now make a table.  You can choose any x values you want, and then calculate y for each one.

x   y

0  0

1   25/11

3  (25/11)*3 = 75/11

Then we have three points on this line: (0,0), (1, 25/11), 3, 75/11).  You could obtain more by choosing additional x values.

boffeemadrid

Some points that lie on the line are required.

Some of the points are [tex](0,-0.545)[/tex], [tex](2,0)[/tex] and [tex](1,-0.273)[/tex].

The equation of the line is [tex]\dfrac{y}{x-2}=\dfrac{3}{11}[/tex]

This can be written as

[tex]y=\dfrac{3}{11}(x-2)\\\Rightarrow y=\dfrac{3}{11}x-\dfrac{6}{11}[/tex]

Finding points

[tex]x=0[/tex]

[tex]y=0-\dfrac{6}{11}=-0.545[/tex]

The point is [tex](0,-0.545)[/tex]

[tex]y=0[/tex]

[tex]0=\dfrac{3}{11}x-\dfrac{6}{11}\\\Rightarrow x=\dfrac{\dfrac{6}{11}}{\dfrac{3}{11}}\\\Rightarrow x=(2,0)[/tex]

The point is [tex](2,0)[/tex]

[tex]x=1[/tex]

[tex]y=\dfrac{3}{11}\times 1-\dfrac{6}{11}\\\Rightarrow y=-\dfrac{3}{11}=-0.273[/tex]

The point is [tex](1,-0.273)[/tex]

The points are [tex](0,-0.545)[/tex], [tex](2,0)[/tex] and [tex](1,-0.273)[/tex].

Learn more:

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