Given equation is y=3x+3 and [tex]\frac{1}{3}y=x+1[/tex]
Let's simplify the 2nd equation [tex]\frac{1}{3}y=x+1[/tex] before we can start graph so that calculation will be easy
[tex]\frac{1}{3}y=x+1[/tex]
multiply both sides by 3 to cancel out fractions
[tex]3*\frac{1}{3}y=3*x+3*1[/tex]
y=3x+3
which is exactly same as the first equation so graph of both will be exactly same and solution will be infinitely many solutions.
y=3x+3 has y-intercept 3 so first point will be (0,3). Slope is 3 so rise 3 unit up then 1 right and graph the new point.
