What is the midpoint of the line segment with endpoints (-1,7) and (3,-3)

A(2,2)
B(1,2)
C(2,4)
D(1,4)

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sid071 sid071 · Answer 1 · 2018-10-14T20:00:00+02:00

Hey there!!

Co-ordinates for midpoint when two endpoints are given :

... [tex]\frac{x2+x1}{2} , \frac{y2+y1}{2}[/tex]

Given endpoints :-

... ( -1, 7 ) ( 3, -3 )

... [tex]\frac{3-1}{2},\frac{-3+7}{2}[/tex]

... [tex]\frac{2}{2},\frac{4}{2}[/tex]

... [tex]1,2[/tex]

Hence, the midpoint is ( 1,2 )

Hope my answer helps!

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shivishivangi1679 shivishivangi1679 · Answer 2 · 2022-06-11T12:07:50+02:00

The midpoint of the line segment with endpoints (-1,7) and (3,-3) would be (1, 2).

Suppose we've two endpoints of a line segment:

A(p,q), and B(m,n)

Then let the midpoint be M(x,y) on that line segment. Then, its coordinates are:

[tex]x = \dfrac{p+m}{2}\\and \\y = \dfrac{q+n}{2}[/tex]

Given endpoints ; ( -1, 7 ) ( 3, -3 )

[tex]x = \dfrac{-1+3}{2}\\\\\\x = 1\\y = \dfrac{7-3}{2}\\\\ y = 2[/tex]

Hence, the midpoint is ( 1,2 ).

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