Answer:
Tthe x-intercepts of f(x)= cosx on [0, 2π ) are:
[tex]\frac{\pi }{2}[/tex] and [tex]\frac{3\pi }{2}[/tex]
Step-by-step explanation:
x-intercept are those values of x for which f(x)=0
So, x-intercept of f(x)=cosx will be those values of x for which
cosx=0
cosx=0 for
[tex]\frac{\pi }{2}[/tex] and [tex]\frac{3\pi }{2}[/tex] on [0, 2π )
Hence, the x-intercepts of f(x)= cosx on [0, 2π ) are:
[tex]\frac{\pi }{2}[/tex] and [tex]\frac{3\pi }{2}[/tex]
