Respuesta :
v₀ = initial speed of the object = 8 meter/second
v = final speed of the object = 16 meter/second
t = time taken to increase the speed = 10 seconds
d = distance traveled by the object in the given time duration = ?
using the kinematics equation
d = (v + v₀) t/2
inserting the above values in the above equation
d = (16 + 8) (10)/2
d = 120 meter
The distance traveled by object is 120 m in 10 seconds.
The kinematic equation for distance is,
[tex]\rm \bold{ d = (V+V_0) \frac{t}{2} }[/tex]
Where,
[tex]\rm \bold { V_0}[/tex] - initial speed = 8 m/s
V- final speed = 16 m/s
t- time = 10 s
Put the values in formula,
[tex]\rm \bold{ d = (16+8) \frac{10}{2} }\\\\\rm \bold{ d =120 m }[/tex]
So, we can conclude that the distance traveled by object is 120 m.
To know more about acceleration, refer to the link:
https://brainly.com/question/24372530?referrer=searchResults
