Respuesta :
As per the question a frog jumps 5 m towards east.
Frog again jumps 2 m north.
Let the displacement along east is denoted by vector A and the displacement towards north is denoted as vector B.
Hence magnitude of A = 5 m
Magnitude of B = 2 m
We are asked to calculate the total displacement.
Here the angle between them is 90 degree as A is towards east and B is towards north.
As per parallelogram law of vector addition,the magnitude of total displacement [R] will be-
[tex]R=\sqrt{ A^{2} +B^{2}+2AB\cos\theta}[/tex]
[tex]=\sqrt{ 5^{2}+ 2^{2}+2*5*2 cos 90}[/tex]
[tex]=\sqrt{25+4+0} m[/tex] [cos90= 0]
[tex]=\sqrt{29} m[/tex]
[tex]= 5.38516 m[/tex] [ans]
