Respuesta :

gmany

[tex]r+\dfrac{2}{3}=\dfrac{3}{8}\ \ \ \ |-\dfrac{2}{3}\\\\r=\dfrac{3}{8}-\dfrac{2}{3}\ \ \ \ |\text{the common denominator is}\ 24\\\\r=\dfrac{3\cdot3}{8\cdot3}-\dfrac{2\cdot8}{3\cdot8}\\\\r=\dfrac{9}{24}-\dfrac{16}{24}\\\\r=\dfrac{9-16}{24}\\\\r=-\dfrac{7}{24}[/tex]

sqdancefan

You can multiply your equation by 24 to eliminate fractions.

... 9 = 24r + 16

Subtract 16 to get the variable term by itself.

... -7 = 24r

Divide by 24 to get the variable by itself.

... -7/24 = r . . . . . . the solution to your equation

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