Since the object is dropped from some height so its initial speed must be zero
acceleration of the object is due to gravity
so we can use kinematics to find the time it will take to drop by x = 22 m
[tex]\delta x = v_i * t + \frac{1}{2}at^2[/tex]
[tex]22 = 0 + \frac{1}{2}*9.8*t^2[/tex]
[tex] t = 2.12 s[/tex]
Now the speed after 2.12 s will be given as
[tex]v_f = v_i + at[/tex]
[tex]v_f = 0 + 9.8 * 2.12[/tex]
[tex]v_f = 20.8 m/s[/tex]
so above is the speed and time
