A hydrogen-filled balloon is ignited and 1.50 g of hydrogen reacts with 12.0 g of oxygen. How many grams of water vapor form? (assume that water vapor is the only product.)

Respuesta :

The balanced chemical reaction between hydrogen and oxygen to form water is given as:

[tex]H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)[/tex]

From the balanced chemical equation it is clear that one mole of hydrogen reacts to give 1 mole of water.

Since, number of moles = [tex]\frac{mass of the substance}{Molar Mass}[/tex]

So, number of moles of hydrogen = [tex]\frac{mass of the hydrogen}{Molar Mass of hydrogen}[/tex]

Mass of hydrogen = [tex]1.50 g[/tex]     (given)

Molar mass of hydrogen, [tex]H_2 = 2\times 1 = 2 g/mol[/tex]

Substituting the values:

Number of moles of hydrogen = [tex]\frac{1.5}{2} = 0.75 mol[/tex]

Number of moles of water formed on reacting with [tex]0.75 mol[/tex] of hydrogen is:

Number of moles of water = [tex]0.75 mol[/tex]

Mass of water can be calculated by:

Number of moles of water = [tex]\frac{mass of water}{Molar Mass of water}[/tex]

Molar mass of water = [tex]2\times 1+16 = 18 g/mol[/tex]

Substituting the values:

[tex]0.75 mol = \frac{mass of water}{18 g/mol}[/tex]

[tex]mass of water = 13.5 g[/tex]

Hence, the mass of water vapor forms is [tex]13.5 g[/tex].