Which values are solutions to the inequality?
​ ​2r≤3r−8​ ​
Select each correct answer.
Points you get if answer: 10!
Answers to choose:
6

7

8

9
I'm sorry i suck at math but please help a gal out

Respuesta :

The correct answers are:

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[C]: " 8 " .      AND :

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[D]:  " 9 " .

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Explanation:

To solve:

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Given:    ​" 2r  ≤  3r − 8​ "  ;

Simplify;  to solve this "inequality" in terms of "r" ;

Subtract  "3r" from EACH SIDE of the equation:

   →   2r − 3r  ≤  3r − 8​ − 3r  ;

to get:

   →  - 1r  ≤  -8  ;

Now,  divide both sides of this "inequality" by "-1" ;

   to isolate "r" on one side of the "inequality" ; and to solve; 'in terms of "r" ;

Note: When you multiply or divide each side of an inequality;

                   →   by a "negative value" ;  you ALWAYS reverse the "sign" of the inequality (switch the direction of the "sign").

So:  

   →      - 1r  ≤  -8  ;

Divide each side by:    " -1 "  ;

to get:

   →      - 1r / -1   ≤   -8 /  -1    ;

to get:

   →  {remember to reverse the direction of the sign} ;  

         →    "   r    ≥    8  "  .

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So:  given the answer choices:  " 6, 7 , 8 , and 9" ;

 →  Which of these numbers, if any, when substituted for "r" in the "inequality" ;  hold true?

 →  Begin;  with:   " r = 6 "  ;    →   " 6     8  " ?  ;  No.

 →  Continue;   with:  " r = 7 "  ;   →  " 7     8  " ?  ;  No.

 →  Continue;   with:  " r = 8 "  ;   →  " 8    8  " ?  ; Yes!  

                                                →  {Note:  Is "8" greater than; OR equal to; "8" ?

                                                             →  " 8 = 8 " ;  →  so; " 8 " is equal to " 8 " !

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→  Continue;   with:   " r = 9 "  ;   →  " 9     8  " ?  ;  Yes!  

                                               →  {Note:  Is " 9 " greater than; OR equal to; " 8 " ?

                                                        →  " 9  > 8 " ;  →  so; "9" is greater than " 8 " !

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  →   As such:  the correct answers are:

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[C]: " 8 " .      AND :

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[D]:  " 9 " .

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Hope this helps!

Best wishes in your academic endeavors —

  and within the "Brainly" community!

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