True.
Distribute 3 to all terms within the parenthesis
3(4h + 2k) = 3(4h) + 3(2k) = 12h + 6k
hope this helps
[tex]12h+6k=3\cdot4h+3\cdot2k=3(4h+2k)[/tex]
Answer: Yes. 12h + 6k is equivalent to 3(4h + 2k)