we are given
Point A lies on the circumference of the unit circle
so, we can write equation of circle as
[tex]x^2 +y^2 =1^2[/tex]
now, we are given
[tex]x =0.12[/tex]
so, we can plug it in equation and find y
[tex]0.12^2 +y^2 =1^2[/tex]
[tex]y^2=0.9856[/tex]
[tex]y=\sqrt{0.9856},\:y=-\sqrt{0.9856}[/tex]
Since, point-A lies in first quadrant
so, both x-value and y-value will be positive
so, we get
[tex]y=\sqrt{0.9856}[/tex].............Answer
Answer
0.99
Explanation
Point A forms a right triangle.
Hypotenuse, c = 1 unit
Base length, x = 0.12 units
Then using the Pythagoras theorem,
y² = c² - x²
y² = 1² - 0.12²
= 2 - 0.0144
= 0.9856
y = √0.9856
= 0.992773891
Answer to the nearest hundredths is 0.99.
