∆ADC is formed by reflecting ∆ABC across line segment , as shown in the figure. If the length of is 4 units, the area of ∆ADC is ________ square units.

Answer - 6 sq.units
Solution - As the triangle ADC is the reflection of the triangle ABC, so the area of both the triangles will be same.
Here BE is the height and AC is the base of ABC.
Area of triangle ABC = [tex]\frac{1}{2}[/tex]×Base×Height
= [tex]\frac{1}{2}[/tex]×3×4
= 6 sq.units
So the area of triangle ADC = 6 sq.units