A certain element (X) has isotopes with mass numbers of 10 and 11. The X-10 isotope has an atomic mass of 10.013, and it represents 19.9% of all atoms of this element. The X-11 isotope has an atomic mass of 11.009, and it represents 80.1% of all atoms of this element. Therefore, the average atomic mass, or atomic weight, of this element is amu.

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The average atomic mass of element X is 10.81 u.

The average atomic mass of X is the weighted average of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).

Thus,  

0.199 × 10.013 u =   1.993 u

0.801 × 11.009 u =  8.818 u

             TOTAL =  10.81  u

Answer:

[tex]m=10.811 amu[/tex]

Explanation:

The average atomic mass in amu is calculated using the following formula

[tex]m=\frac{(m_{1} \%m_{1})+(m_{2} \%m_{2})}{100 \%}[/tex]

[tex]m_{1}= 10.013\\ \%m_{1}= 19.9\%(abundance)\\ m_{2}= 11.009\\ \%m_{2}= 80.1\%(abundance)[/tex]

[tex]m=\frac{((10.013).(19.9\%))+((11.009) (80.1\%))}{100 \%}\\ m=10.811 amu[/tex]