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The normal boiling point of methanol is 64.7°c. A solution containing a nonvolatile solute dissolved in methanol has a vapor pressure of 649.2 torr at 64.7°c. What is the mole fraction of methanol in this solution?

Respuesta :

znk

The mole fraction of methanol is 0.8542.

Raoult’s Law: p = χp°

χ = p/p° = 649.2 torr/760 torr = 0.8542

samueladesida43

The mole fraction of methanol in the solution of methanol is 0.8542

HOW TO CALCULATE MOLE FRACTION:

  • The mole fraction of a solvent can be calculated using Raoult's law equation as follows:

P = Χ × P⁰

Where,

  1. P = vapour pressure of the solution
  2. Χ = mole fraction of the solvent
  3. P⁰ = vapour pressure of the pure solvent

  • According to this question, a solution containing a nonvolatile solute dissolved in methanol has a vapor pressure of 649.2 torr at 64.7°C.

X = P/P⁰

X = 649.2torr/760torr

X = 0.8521

Therefore, the mole fraction of methanol in the solution of methanol is 0.8542.

Learn more about mole fraction at: https://brainly.com/question/2060778

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