Respuesta :
It is given that the person weighs 62 kg = 62,000 g
Natural abundances in mass percent are:
O = 65%
C = 18%
H = 10%
N = 3.0%
Ca = 1.6%
P = 1.2%
Corresponding weights of the elements are:
O = 65/100 * 62000 g = 40.30 * 10^3 g
C = 18/100 * 62000 g = 11.16 * 10^3 g
H = 10/100 * 62000 g = 62.00 * 10^2 g
N = 3.0/100 * 62000 g = 18.60 * 10^2 g
Ca = 1.6/100 * 62000 g = 9.92 * 10^2 g
P = 1.2/100 * 62000 g = 7.44 * 10^2 g
Answer:
O: 4.2 × 10⁴ g
C: 1.2 × 10⁴ g
H: 6.4 × 10³ g
N: 1.9 × 10³ g
Ca: 1.0 × 10³ g
P: 7.7 × 10² g
Other elements: 7.7 × 10² g
Explanation:
Natural abundances of elements in the human body (in percent by mass)
- oxygen (O), 65%
- carbon (C), 18%
- hydrogen (H), 10%
- nitrogen (N), 3.0%
- calcium (Ca), 1.6%
- phosphorus (P), 1.2%
- all other elements, 1.2%
The mass of a body is 64 kg = 64 × 10³ g = 6.4 × 10⁴ g. We can calculate the mass of each element by multiplying the body weight by the mass percent of each element.
O: 6.4 × 10⁴ g × 65% = 4.2 × 10⁴ g
C: 6.4 × 10⁴ g × 18% = 1.2 × 10⁴ g
H: 6.4 × 10⁴ g × 10% = 6.4 × 10³ g
N: 6.4 × 10⁴ g × 3.0% = 1.9 × 10³ g
Ca: 6.4 × 10⁴ g × 1.6% = 1.0 × 10³ g
P: 6.4 × 10⁴ g × 1.2% = 7.7 × 10² g
Other elements: 6.4 × 10⁴ g × 1.2% = 7.7 × 10² g