Answer:- 14.0 moles of hydrogen present in 2.00 moles of [tex] [tex]C_6H_7N[/tex] .
Solution:- We have been given with 2.00 moles of [tex]C_6H_7N[/tex] and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:
[tex]2.00molC_6H_7N(\frac{7molH}{1molC_6H_7N})(\frac{1.0gH}{1molH})[/tex]
= 14.0 g H
So, there are 14.0 g of hydrogen in 2.00 moles of [tex]C_6H_7N[/tex] .
