|A| = magnitude of the vector [tex]\underset{A}{\rightarrow}[/tex]= 10 units
θ = angle of the vector [tex]\underset{A}{\rightarrow}[/tex] relative to positive x-axis = 30 degree
A' = component of vector [tex]\underset{A}{\rightarrow}[/tex] parallel to x-axis
Since the angle is made with the x-axis, hence the x-component of the vector [tex]\underset{A}{\rightarrow}[/tex] is given as
A' = |A| Cosθ
A' = (10) Cos30
A' = (10) (0.866)
A' = 8.66 units
There are [tex]5\sqrt{3}[/tex] units in the x-axis.
A vector represented in polar format is defined by the following form:
[tex]\vec v = (r,\theta)[/tex] (1)
Where:
And the magnitude of the vector in the x-direction:
[tex]x = r\cdot \cos \theta[/tex] (2)
If we know that [tex]r = 10[/tex] and [tex]\theta = 30^{\circ}[/tex], then the magnitude of the vector in the x-direction is:
[tex]x = 10\cdot \cos 30^{\circ}[/tex]
[tex]x = 5\sqrt{3}[/tex]
There are [tex]5\sqrt{3}[/tex] units in the x-axis.
We kindly invite to check this question on vectors: https://brainly.com/question/21925479
