we are given
[tex]P=2e^{-0.5t}[/tex]
we can rewrite it as
[tex]P=2(e^{-0.5})^t[/tex]
[tex]e^{-0.5}=0.6065[/tex]
now, we can replace it
we get
[tex]P=2(0.6065)^t[/tex]
now, we can compare it with
[tex]P=P_0(a)^t[/tex]
and find a
[tex]a=0.6065[/tex]
Since, a=0.6065<1
so, it is exponential decay function..........Answr