rainbow85
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Shelley's basketball team won 3/4 of their games last season. In 1/6 of the games they won, they outscored their opponents by more than 10 points. What fraction of their games did Shelley’s team win by more than 10 points?

Respuesta :

JannetPalos

Let the total number of games be x.

Number of games Shelley's team won = [tex]\frac{3}{4} x[/tex]

Number of games they outscored

their opponents by more than 10 points = [tex]\frac{1}{6}[/tex] × [tex]\frac{3}{4} x[/tex]

= [tex]\frac{1}{8} x[/tex]

Hence, 1/8 of the total games, Shelley's team won by 10 points.

Answer:

[tex]\frac{1}{8}[/tex]

Step-by-step explanation:

This problem can be resolved with a simple multiplication, but the important thing is to analyse and know why.

First of all, this problem can be seen as a probability problem with two events: Games won (Event A) and Games won with more than 10 points (Event B).

Each event have already its probability. For Event A we have [tex]\frac{3}{4}[/tex]. For Event B we have [tex]\frac{1}{6}[/tex].

So, the fact that it's being asked for the expression when they won and with more than 10 points, means an interception, a mixture of both events. In order to that ''mixture'', mathematically we multiply, because we need to calculate games won and with more than 10 points.

[tex]\frac{3}{4} . \frac{1}{6} = \frac{3}{24}  = \frac{1}{8}[/tex]

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