Respuesta :
to write in standard form
make the value in between (1 - 9.9) by placing a dot
= 4.2
count the number of times you moved the dot.
Left means to a - power
Right means to a + power
(Don't forget to put ×10, it is the most essential thing that allow you to move the decimal place)
= 4.2×10^1
To check answer:
Anything to power one is the value itself
10^1 = 10
So, 4.2 × 10 = 42
make the value in between (1 - 9.9) by placing a dot
= 4.2
count the number of times you moved the dot.
Left means to a - power
Right means to a + power
(Don't forget to put ×10, it is the most essential thing that allow you to move the decimal place)
= 4.2×10^1
To check answer:
Anything to power one is the value itself
10^1 = 10
So, 4.2 × 10 = 42
Answer:
char numb[2];
numb[0] = 52;
numb[1] = 50;
Print as a string
printf("%s\n", numb)
Step-by-step explanation:
A string is the same as a vector of char.
We have to find the ASCII values of '4' and '2'
'4' has an ASCII value of 52
'2' has an ASCII value of 50
Expression:
char numb[2];
numb[0] = 52;
numb[1] = 50;
Print as a string
printf("%s\n", numb)