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If a plant manufacturing carpet backing has a cylindrical tank that is 3 meters high and is 6 meters in diameter, what is the volume of the tank? Assume 3.14 for pi. A) 28.3 m3 B) 37.7 m3 C) 56.5 m3 Eliminate D) 84.8 m3

Respuesta :

olemakpadu
For a cylindrical tank, volume = πr²h

Where r = radius = diameter/2 = 6/2 = 3m
height , h = 3m

Volume  =  3.14 * 3² * 3 = 84.78

Volume ≈ 84.8 m³

Option D.
boffeemadrid

Answer:

(D) [tex]V[/tex]≈[tex]84.8m^3[/tex]

Step-by-step explanation:

It is given that If a plant manufacturing carpet backing has a cylindrical tank that is 3 meters high and is 6 meters in diameter, thus the radius of the cylindrical tank is given as:

[tex]Diameter=\frac{Radius}{2}=\frac{6}{2}=3m[/tex]

and the height is=6m.

Now, the volume of the cylindrical tank is given as:

[tex]V={\pi}r^2h[/tex]

Substituting the given values, we get

[tex]V=3.14(3)^2(3)[/tex]

[tex]V=3.14(27)[/tex]

[tex]V=84.78m^3[/tex]

[tex]V[/tex]≈[tex]84.8m^3[/tex]

Hence, the volume of the cylindrical tank is [tex]84.8m^3[/tex].

Thus, option D is correct.

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