Answer:
1. False, a common factor of a trinomial is composed of a bimony as long as it is consistent with the perfect square trinomial rule
2. True, a common factor is the product that give back the original bimony
3. False, doesn't fit the perfect square trinomial rule
Step-by-step explanation:
1. Taking a trinomial in the way:
[tex]a^{n}+2*a*b+b^{n}[/tex]
that's perfect square trinomial and is composer of a squared binomial
So, any expression in the way trinomial for example:
[tex]x^{5}+4x^{2}+4[/tex] that no fit as the square trinomial rule can't be resolved with an binomy
2. The expression:
[tex]3x^{2} + 5 x-8[/tex]
So the factor [tex](3x+8)[/tex] using synthetic division give as a factor with [tex](x-1)[/tex]
check doing multiplication:
[tex](3x+8)*(x-1)= 3x^{2} +8x-3x-8[/tex]
[tex]3x^{2} +5x-8[/tex]
3.The expression:
[tex]a^{4} -14m^{2} +49[/tex] different values in the independent variable a at the higher and m in the second however if they were the same in this way:
[tex]a^{4} -14a^{2} +49[/tex] it will be a perfect square trinomial
[tex](a-7)^{2}[/tex] and this will be the binomial factor
