Method 1.
[tex]y > 3x+8\\\\y=3x+8\\for\ x=0\to y=3(0)+8=8\to(0,\ 8)\\for\ x=-3\to y=3(-3)+8=-1\to(-3,\ -1)\\\\y\leq-\dfrac{1}{2}x+4\\\\y=-0.5x+4\\for\ x=0\to y=-0.5(0)+4=4\to(0,\ 4)\\for\ x=4\to y=-0.5(4)+4=2\to(4,\ 2)[/tex]
Look at the picture.
Answer: (-4, 2).
Method 2.
[tex](2,\ 5)\to x=2,\ y=5\\\\5 > 3(2)+8\\5 > 14\ FALSE\\\\(1,\ -1)\to x=1,\ y=-1\\\\-1 > 3(1)+8\\-1 > 11\ FALSE\\\\(-4,\ 2)\to x=-4,\ y=2\\\\2 > 3(-4)+8\\2 > -4\ TRUE\\\\2\leq-\dfrac{1}{2}(-4)+4\\2\leq2+4\\2\leq6\ TRUE\\\\Answer:\ (-4,\ 2)[/tex]
