Assuming constant acceleration due to gravity of [tex]a=9.8\,\dfrac{\mathrm m}{\mathrm s^2}[/tex], and assuming the passengers start at rest, so that [tex]v_0=0\,\dfrac{\mathrm m}{\mathrm s}[/tex], we have
[tex]v=v_0+at\implies v=\left(9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(5.5\,\mathrm s)=53.9\,\dfrac{\mathrm m}{\mathrm s}[/tex]
or 54 m/s if taking significant digits into account.
Answer:
Assuming constant acceleration due to gravity of , and assuming the passengers start at rest, so that , we have or 54 m/s if taking significant digits into account.
Explanation:
