With total velocity [tex]v=2.0\,\dfrac{\mathrm m}{\mathrm s}[/tex], the horizontal component of velocity is
[tex]v_x=\left(2.0\,\dfrac{\mathrm m}{\mathrm s}\right)\cos15.0^\circ\approx1.93\,\dfrac{\mathrm m}{\mathrm s}[/tex]
Then the horizontal displacement over the first minute is
[tex]s_x=\left(1.93\,\dfrac{\mathrm m}{\mathrm s}\right)(60\,\mathrm s)\approx116\,\mathrm m[/tex]
