[tex] \bf (\stackrel{x_2}{-4}~,~\stackrel{y_2}{6})\qquad \qquad \qquad
slope = m\implies -2
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\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-6=-2[x-(-4)]
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y-6=-2(x+4)\implies y-6=-2x-8\implies y=-2x-2\\\\
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(\stackrel{x_2}{2}~,~\stackrel{y_2}{5})\qquad \qquad \qquad
slope = m\implies 1
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\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-5=1(x-2)
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y-5=x-2\implies y=x+3 [/tex]
The slope-intercept form: y = mx + b
1. m = -2 → y = -2x + b
(-4, 6) → x = -4, y = 6, substitute:
6 = -2(-4) + b
6 = 8 + b |-8
b = -2
Answer: y = -2x - 2
2. m = 1 → y = 1x + b
(2, 5) → x = 2, y = 5, substitute:
5 = 1(2) + b |-2
b = 3
Answer: y = x + 3
