Respuesta :
[tex]\dfrac{5}{6}x-\dfrac{1}{3} > 1\dfrac{1}{3}\\\\\dfrac{5}{6}x-\dfrac{1}{3} > \dfrac{4}{3}\ \ \ \ |\cdot6\\\\5x-2 > 2\cdot4\\\\5x-2 > 8\ \ \ \ |+2\\\\5x > 10\ \ \ \ |:5\\\\x > 2\to x\in(2;\ \infty)[/tex]
[tex]\dfrac{5}{6}x-\dfrac{1}{3} > 1\dfrac{1}{3}\\\\\dfrac{5}{6}x-\dfrac{1}{3} > \dfrac{4}{3}\ \ \ \ |\cdot6\\\\5x-2 > 2\cdot4\\\\5x-2 > 8\ \ \ \ |+2\\\\5x > 10\ \ \ \ |:5\\\\x > 2\to x\in(2;\ \infty)[/tex]