Respuesta :

Banabanana

[tex] 64^x = 16^{x-1} \\\\ (4^3)^x=(4^2)^{x-1} \\\\ 4^{3x}=4^{2x-2}\\\\ 3x=2x-2 \\\\ \boxed{x=-2} [/tex]

I am assuming that x - 1 is the exponent of 16


64^x = 16^(x-1)


4^3x = 4^(2x-2)


3x = 2x - 2


x = -2 answer