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Three brothers have ages that are consecutive odd integers. The difference between the age of the oldest and twice the age of the youngest is twenty-four less than the middle brother's age Find their ages.

Respuesta :

livefranoor5w13

N, N+2, and N + 4 are the ages


(N + 4) - (2N) = (N + 2) -24


4 - N = N - 22


2N = 26

N = 13

The brothers are 13, 15, and 17 years old.

HOPE THIS HELPS!!

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