bearing in mind that the volume of a pyramid is the product of the area of its base and its height, now, this one has a rectangular base of 5x7, so its base area is 35.
[tex] \bf \textit{volume of a pyramid}\\\\
V=\cfrac{1}{3}Bh~~
\begin{cases}
B=area~of\\
\qquad its~base\\
h=height\\
------\\
V=\stackrel{in^3}{105}\\
B=\stackrel{5\times 7}{35}
\end{cases}\implies 105=\cfrac{1}{3}(35)h
\\\\\\
3(105)=35h\implies 315=35h\implies \cfrac{315}{35}=h\implies 9=h [/tex]
Answer:
Sample Response: Substitute the area of the base and the volume into the formula V = 1
3
Bh. After substituting, you have 105 = 1
3
(35)h. Solve for h by multiplying both sides by 3 and then dividing both sides by 35. The height is 9 inches.
Step-by-step explanation:
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